Programmieren lernen

import re
string='slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb'
ABC={chr(i):i-96 for i in range(97,123)}
print(sum([ABC[a] for a in re.findall('[a-z]',string.lower())]))
                

Lösung von: rob ert (tub)

s="slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb"
print(sum((ord(c)-ord('a')+1 for c in s.lower() if 'a' <= c <= 'z')))
                

Lösung von: Name nicht veröffentlicht

function letterSum(str) {
  let sum = 0;
  str = str.toUpperCase().replace(/[^A-Z]/g, '');
  for (let i = 0; i < str.length; i++)
    sum += str.charCodeAt(i) - 64;
  return sum;
}

let w = `slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb`;
console.log( letterSum(w) );
                

Lösung von: Lisa Salander (Heidi-Klum-Gymnasium Bottrop)

// NET 7.x | C# 11.x | VS-2022
var txt = "slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc., fueodoqiewncvnwofuwb";
Console.WriteLine(txt.ToLower().Where(char.IsLetter).Select(x => x - 96).Sum());
                

Lösung von: Jens Kelm (@JKooP)

// C++ 14 | VS-2022
#include <iostream>
#include <algorithm>
#include <numeric>

auto sum_of_char_values(const std::string& txt) {
    auto str{ txt };
    std::transform(str.begin(), str.end(), str.begin(), ::tolower);
    return std::accumulate(str.begin(), str.end(), 0, [](auto a, auto b) { return a + (std::isalpha(b) ? (b - 96) : 0); });
}

int main() {
    const std::string txt{ "slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb" };
    std::cout << sum_of_char_values(txt) << "\n";
}
                

Lösung von: Jens Kelm (@JKooP)

// NET 7.x | C# 11.x | VS-2022
using System.Text.RegularExpressions;

int SumOfCharValues2(string txt) {
    var sum = 0;
    foreach (var c in txt) {
        if (char.IsAsciiLetterLower(c)) sum += c - 96;
        else if (char.IsAsciiLetterUpper(c)) sum += c - 64;
    }
    return sum;
}

int SumOfCharValues3(string txt) => new Regex(@"[a-z]").Matches(txt.ToLower()).Select(x => x.Value[0] - 96).Sum();
                

Lösung von: Jens Kelm (@JKooP)

// C++ 14 | VS-2022
#include <iostream>

auto sum_of_char_values2(const std::string& txt) {
    auto sum{ 0 };
    for (const auto& c : txt) {
        if (c >= 'A' && c <= 'Z') sum += (c - 64);
        else if (c >= 'a' && c <= 'z') sum += (c - 96);
    }
    return sum;
}

int main() {
    const std::string txt{ "slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb" };
    std::cout << sum_of_char_values2(txt) << "\n";
}
                

Lösung von: Jens Kelm (@JKooP)

// C++ 14 | VS-2022
#include <iostream>
#include <numeric>

int main() {
    const std::string str{ "slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb" };
    const auto sum{ std::accumulate(str.begin(), str.end(), 0, [](auto a, auto b) { return a + (std::isalpha(b) ? (std::islower(b) ? (b - 96) : (b - 64)) : 0); }) };
    std::cout << sum << "\n";
}
                

Lösung von: Jens Kelm (@JKooP)

' VBA
Function CharIsAlpha(ByVal s$)
    tmp$ = Asc(Left(s, 1))
    CharIsAlpha = tmp > 96 And tmp < 123
End Function

Function SumOfCharValues(txt$)
    Dim sum%
    txt = LCase(txt)
    For i% = 1 To Len(txt)
        tmp$ = Mid(txt, i, 1)
        If CharIsAlpha(tmp) Then
            sum = sum + (Asc(tmp) - 96)
        End If
    Next i
    SumOfCharValues = sum
End Function

Sub Main()
    Const txt As String = "slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb"
    Debug.Print SumOfCharValues(txt)
End Sub
                

Lösung von: Jens Kelm (@JKooP)

#include <stdio.h>
#include <ctype.h>
#include <string.h>

unsigned(*fun_ptr)(char);

unsigned chr2num(char chr) {
    return isalpha(chr) ? (islower(chr) ? chr - 96 : chr - 64) : 0;
}

int accumulate(const char* string, unsigned begin, unsigned end, int init, unsigned(*fun_ptr)(char)) {
    unsigned sum = init;
    for (unsigned i = begin; i <= end; ++i)
        sum += (*fun_ptr)(string[i]);
    return sum;
}

int main() {
    const char* str = "slkdfjb543--..wdwnsmwqpieo  fubwicbxoiwkewdioefncwbviwrc.,  fueodoqiewncvnwofuwb";
    int res = accumulate(str, 0, strlen(str), 0, &chr2num);
    printf("%i", res);
}
                

Lösung von: Jens Kelm (@JKooP)