Programmieren lernen

import java.util.Scanner;

/**
 * @author Philipp Gressly (phi AT gressly DOT ch)
 */
public class Wertetabelle {
  public static void main(String[] args) {
    new Wertetabelle().top();
  }

  void top() {
    double a = einlesen("a");
    double b = einlesen("b");
    double c = einlesen("c");
    double start = einlesen("start");
    double end = einlesen("end");
    double intervall = einlesen("intervall");

    tabelle(a, b, c, start, end, intervall);
  }

  void tabelle(double a, double b, double c, double start, double end,
      double intervall) {
    double aktuell = start;
    while (aktuell <= end) {
      double wert = quadratischeFunktion(aktuell, a, b, c);
      System.out.println(aktuell + " -> " + wert);
      aktuell = aktuell + intervall;
    }

  }

  double quadratischeFunktion(double x, double a, double b, double c) {
    return a * x * x + b * x + c;
  }

  Scanner sc = new Scanner(System.in);
  double einlesen(String groesse) {
    System.out.println("Geben Sie " + groesse + " ein: ");
    return sc.nextDouble();
  }
  
} // end of class Wertetabelle
                

def werteQuadFkt(a,b,c,start,stop,intervall):
    x = start
    xlist  = []
    while (x <= stop):
        xlist.append(x)
        x += intervall
        
    for x in xlist:
        y = a*x*x+b*x+c
        print('x: '+str(x)+'\t'+'y: '+str(y))



a =  5.0
b = -3.0
c =  2.0
start = -5.0
end = 5.0
intervall = 0.5
werteQuadFkt(a,b,c,start,end,intervall)
                

function quadraticFunc(a, b, c, x, xEnd, inc) {
  let arr = [];
  for (x; x <= xEnd; x += inc)
    arr.push([x, a * (x ** 2) + b * x + c]);
  return arr;
}

function cubicFunc(a, b, c, d, x, xEnd, inc) {
  let arr = [];
  for (x; x <= xEnd; x += inc)
    arr.push([x, a * (x ** 3) + b * (x ** 2) + c * x + d]);
  return arr;
}

console.table(quadraticFunc(5, -3, 2, -5, 5, 0.5));
console.table(cubicFunc(5, 4, 3, 2, -5, 5, 0.5));
                

Lösung von: Lisa Salander (Heidi-Klum-Gymnasium Bottrop)

// NET 6.x | C# 10.x | VS-2022

static IEnumerable<(double x, double y)> Equations(double start, double end, double step, params double[] param) {
    for (var x = start; x <= end; x += step) {
        var y = 0.0;
        for (var k = param.Length - 1; k >= 0; k--)
            y += Math.Pow(x, k) * param[^(k + 1)];
        yield return (x, y);
    }
}

static void PrintEquations(IEnumerable<(double x, double y)> lst) => lst.ToList().ForEach(i => Console.WriteLine($"{i.x,10:f}\t{i.y,10:f}"));

var quadratic = Equations(-5, 5, 0.5, 5, -3, 2);
PrintEquations(quadratic);

var cubic = Equations(-5, 5, 0.5, 5, -3, 3, 2);
PrintEquations(cubic);
                

Lösung von: Jens Kelm (@JKooP)

// C++ 20 | VS-2022

#include <iostream>
#include <vector>
#include <tuple>
#include <ranges>
#include <iomanip>

std::vector<std::tuple<double, double>> equations(double start, double end, double step, std::vector<double> param) {
    const auto ps{ (int)param.size() };
    std::vector<std::tuple<double, double>> out{};
    for (auto x{ start }; x <= end; x += step) {
        auto y{ 0.0 };
        for (auto k{ ps - 1}; k >= 0; k--)
            y += pow(x, k) * param[static_cast<long long>(ps)-k-1];
        out.push_back({ x, y });
    }
    return out;
}

void print(std::vector<std::tuple<double, double>> v) {
    for (const auto& [x, y] : v) { // C++ 20
        std::cout << std::fixed << std::setprecision(2) << "x: " << x << std::setw(15) << "y: " << y << "\n";
    }
}

int main() {
    const auto quadratic{ equations(-5, 5, 0.5, {5, -3, 2 }) };
    const auto cubic{ equations(-5, 5, 0.5, { 5, -3, 3, 2 }) };
    print(quadratic);
    print(cubic);
}
                

Lösung von: Jens Kelm (@JKooP)